 Hi, and welcome to the session. Let us discuss the following question. The question says, show that the equation of the line passing through the origin and making an angle theta with the line y is equal to mx plus c is y by x is equal to plus minus m plus tan theta upon 1 minus m tan theta. This is the question in whose equation is y is equal to mx plus c to the origin and making angle theta with vq. x is equal to plus theta upon 1 minus m whose equation is y is equal to mx plus c m1. Now as a v makes angle theta vq therefore theta is equal to plus minus m1 minus m upon 1 into m because angle between two lines having slope m1 and m2 is given by tan theta is equal to mod of m2 minus m1 upon 1 plus m1 into m2. Now this implies m1 m tan theta is equal to plus minus m1 minus m implies is equal to into 1 minus m tan theta. And this implies m1 is equal to plus minus m plus tan theta m tan theta. Now we know that equation of line passing through point x1 y1 and having slope m is y minus y1 is equal to m into x minus x1. The line a v is passing through the origin that means x1 y1 is 0 and is having slope plus minus m plus tan theta upon 1 minus m tan theta. Therefore equation of a v is 0 is equal to plus minus m plus tan theta upon 1 minus m tan theta into x minus 0. This implies y by x is equal to plus minus m plus tan theta upon 1 minus m tan theta. Hence we have proved that equation of line passing through the origin and making an angle theta with the line y is equal to mx plus c is y by x is equal to plus minus m plus tan theta upon 1 minus m tan theta. So this concludes the session. Bye and take care.