 I am welcome to the session. Let us discuss the following question. The question says, evaluate limit x approaches pi by 6 root 3 sine x minus cos x divided by x minus pi by 6. I'm beginning with the solution. In this question, we have to evaluate limit x approaches pi by 6 root 3 sine x minus cos x divided by x minus pi by 6. Now we will put as x minus pi by 6. So as x tends to pi by 6, then x tends to 0. Now h equals to x minus pi by 6 implies x is equal to h plus pi by 6. So by substituting h plus pi by 6, h in place of x minus pi by 6, we get, now by using these formulae, we have limit h approaches 0.