 Welcome to the session. I am Deepika here. Let's discuss the question for in the principle value of secant inverse 2 over root 3. Now just look at the table. This table shows the domains and ranges of inverse trigonometric functions. So from this table the range of the principle value branch of secant inverse is close interval 0 to pi excluding pi by 6. So let's start the solution. Root 3 is equal to y then equal to secant pi by 6. Here we know that the range of the principle value branch, the question, I hope the question is clear to you and enjoy yourself.