 Hello and welcome to the session, I am Deepika here. Let's discuss a question which says choose the correct answer in the following. Area of the region bounded by the curve y square is equal to 4x, y axis and the line y is equal to 3 is a, 2, b, 9 over 4, c, 9 over 3 and d 9 over 2. Now we know that by taking horizontal strips the area a of the region bounded by the curve x is equal to gy, y axis and the lines y is equal to c and y is equal to d is given by a is equal to integral from c to d x dy and this is again equal to integral from c to d g of y dy. So this is a key idea behind our question. We will take the help of this key idea to solve the above question. So let's start the solution. We will draw the graph of the region bounded by the curve y square is equal to 4x, y axis and the line y is equal to 3. Now y square is equal to 4x is a parabola with vertex at the origin and symmetrical about x axis and y is equal to 3 is a line parallel to x. The area of this shaded region, the shaded region is the region bounded by the curve y square is equal to 4x, y axis and the line y is equal to 3. So by taking horizontal strips of height x and width dy, the area of the shaded region is integral from 0 to 3 x dy. Now we have y square is equal to 4x, this implies x is equal to y square upon 4. Therefore the required area a is equal to integral from 0 to 3 y square upon 4 dy and this is equal to 1 over 4 into y cube over 3 and the limits are from 0 to 3 and this is equal to 1 over 4 into 3 into 3 cube minus 0 cube which is 0 and this is equal to 1 over 12 into 27 and this is again equal to 9 over 4 and the required area is and this is our option b. So b is the correct answer. So this completes the session. Hope you have enjoyed the session. Bye and take care.