 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question says in figure 8.33 triangle FEC is congruent to triangle GDB and angle 1 is equal to angle 2. Prove that triangle ADE is similar to triangle ABC. In this question we are given that triangle FEC is congruent to triangle GDB and this angle is equal to this angle. We have to prove here that triangle ADE that means this triangle is similar to triangle ABC that means this triangle. So let us start with a solution to this question. Now since it's given to us that triangle FEC is congruent to triangle GDB therefore we will have this angle is equal to this angle. So because triangle FEC is congruent to triangle GDB therefore angle ABC is equal to angle ACB and since angle ABC is equal to angle ACB therefore AB is equal to AC because we see that opposite sides of equal angles are equal. Also angle 1 is equal to angle 2 and that is given to us and since angle 1 is equal to angle 2 therefore AE is equal to AD because sides opposite to equal angles are also equal. So therefore AD is equal to AE. Now we name this 1 and we name this 2 so from 1 and 2 then triangle ADE and triangle ABC we have AD over AB is equal to AE over AC and also the angle enclosed between them that is angle A is equal to angle A that is common. So by this we have triangle ADE is similar to triangle ABC by SAS that is side angle side similarity criterion. So we have proved that triangle ADE is similar to triangle ABC hence proved. So I hope that you understood the question and enjoyed the session. Have a good day.