 Hello and welcome to the session. In this session we will discuss the following question with phase, divide minus 64 a cube b to the power 4 c to the power 5 by 16 a square b square c square. Let's move on to the solution. In this question we are supposed to divide one monomial by the other monomial. We have to divide minus 64 a cube b 4 c 5 by the other monomial 16 a square b square c square. So we have to divide these two monomials. This could also be written as minus 64 a cube b 4 c 5 upon 16 a square b square c square. Now when we have to divide a monomial by another monomial, we first divide the numerical coefficients that is we would divide minus 64 by 16 minus 64 by 16 and this is multiplied by the result that we obtain by dividing the literal coefficients that is a cube b 4 c 5 upon a square b square c square. Now we know 16 4 times is 64. So we get this is equal to minus 4 into now a cube by a square would give us a to the power 3 minus 2 into b to the power 4 minus 2 into c to the power 5 minus 2. So this is further equal to minus 4 into a to the power 1 into b to the power 2 into c to the power 3 that is this is equal to minus 4 a b square c cube. So on dividing the two monomials minus 64 a cube b 4 c 5 by the monomial 16 a square b square c square we get the answer as minus 4 a b square c cube. So this is our final answer. This completes the session. Hope you have understood the solution of this question.