 Hello and welcome to the session. My name is Mansi and I am going to help you with the following question. The question says find the equation of a circle with center 2 2 and passes through the point 4 5. So before starting the solution let us see that equation of the circle with center at h k and radius r is given by x minus h the whole square plus y minus k the whole square equals to r square. Let us start with the solution to this question. First of all we put x y to be equal to 4 5 and h k to be equal to 2 2 in this equation a because it is given to us that the circle passes through the point 4 5 and it has its center at the point 2 2. So we get 4 minus 2 the whole square plus 5 minus 2 the whole square is equal to r square or now 4 minus 2 is 4 the whole square so it is 2 square is 4 4 plus 9 is equal to r square or r square is equal to 13. Now putting the point h k as 2 2 and r square as 13 in this equation we get x minus 2 the whole square plus y minus 2 the whole square is equal to 13 or we can write it as x square plus 4 minus 4 x plus y square plus 4 minus 4 y is equal to 13 or x square plus y square minus 4 x minus 4 y is equal to 13 minus 4 minus 4 and that is 5. So this is equal to 5 so our answer to this question is x square plus y square minus 4 x minus 4 y is equal to 5. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.