 Kori house, heading right down this one, right down in this reaction, this one, this is, this reaction, alkyl halide is treated with, alkyl halide is treated with lithium dialkyl cube red. This is LiR2C, lithium dialkyl cube red, following up the reaction with alkyl halide, following up the reaction with alkyl halide to form alkene. I will write down the three different steps here. Suppose the first step we are using Cf3Br, in presence of dry ether. So this forms CS3 Li, LiBr. Now two modes of this CuCl and it forms Li CS3 to Cu, right? This is di, lithium dialkyl cube red. Now the reaction is Kori house synthesis. This is the method of preparation of this reagent of Kori house synthesis. Now we have an alkyl and I suppose we have C2H5Br. It is allowed to react with this Li CH3. The product is C2H5CH3 plus what we get Cu metal with this. Tertiary halide we do not use here. We do not use tertiary halide. This cannot be tertiary. Must not be tertiary because tertiary halide goes under elimination reaction. This is step, the last step is SN2 mechanism. SN2 is this thing. You get this reaction is the preparation of this reagent, dialkyl cube red. So you get this by this reaction and now this is allowed to react with an alkyl. So this reaction, Kori house synthesis is the main reaction is this. This two reaction is the preparation of the reagent. You know one of the students got 99.97% in chemistry. You can see at top 100 you can see. Overall Palsatal is not that good. It is around 99. But in chemistry it is 99.99. Now it is 99.99. And it is not even 99. But see 99 points overall Palsatal is 99.72. This is around 2.30 some marks out of 300. This is percentile. No in chemistry this. This is, this will be around 3000 or something. This is total percentile cube. This was only for chemistry. So I was happy. What is this? 99.9. 97 chemistry so it is good like top 100 or 200. But overall this percentile was 99. something. So that will be around top 8. 1000 or something. 100. 90 is top 100. 99 is top 100. Okay see SN2. SN2 stands for second order and you don't ask me what is order. Second order new blue philic substitution reaction. What are the reaction is 2. And it is new substitution of new blue philic. Okay the important point here 2 points are important. This is one step reaction. One step reaction. No intermediate forms. One, two, three, four, five, six, seven, eight. One, two, three, four, five, six, seven, eight. There is one more type of reaction. There are many reactions in this. SNi, SN1, another reaction is SN1. SN1 reaction is first order new blue philic substitution. Okay this is the difference is it is two steps and in this the intermediate forms like carbocation. Always carbocation. Mostly it is carbocation. Okay in detail we will discuss all this. But whenever intermediate forms if it is carbocation then rearrangement is possible. Rearrangement of carbocation we have discussed. We will discuss them. Basically we will try to get more stable carbocation. If one degree carbocation you are getting then we will try to get two degree or three degree like that. So it is like the different products. Different products you will get. But according to the most stable carbocation you will get the major product. Others will be minor. Okay now in this reaction in one step reaction what happens here? This methyl CH3 this is CH3 CH2 Br from here CH3 minus CH3 minus it behaves as a nucleophile. So this bond is again polar. More electronegative, delta negative it is delta positive. So this was the density to attack on to this positive charge carbonyl. So when it is trying to make a bond with this carbon this bond is getting weak and it is about to leave. Right so we will have an intermediate stage in between. The intermediate stage is like this. CH3 CH CH3 So what is the point of the first phase that I think how it is? It is actually produced because methyl high also. So my point of view is that what I like to leave. I hope I can't do this. In this molecule it takes like RLGX R minus RLGX. Similar kind here. I am explaining this way. So then in the left hand it has to be LICH3 twice. See you can have another reagent. But since it is a name reaction polyhosphoryl. So for name reaction the reagent everything is mistaken. This is just that guy. Yes yes yes. It would always NA. Like frankly always zinc. But it is technically possible to use it. It is possible but the name is not right. Yes such a thing. See actually this like RLGX R minus is there. So in this molecule CH3 minus is there a reagent here. Nucleophile. Right so this nucleophile attacks on to this carbon. Why because this bond is called a delta positive or negative. Right so this negative charge on to this BF is a nucleophile. It has tendency to attack on to this positive charge carbon. And when this attacks over here this ion or this BR minus has an instant relief in this molecule. So you will get an intermediate stage in between. You see in this stage the carbon has 5 bonds. Which is not stable right. So what happens when this bond is trying to form this bond. This will go out. So eventually what happens. BR minus terms out from this molecule. And this attached with this carbon. You see the carbon atom which has bromine here. That will attach with this with helipad. It goes out and LI combines with this. What not what molecule. It is a nucleophile. It is a nucleophile. Attack on to this. BR minus go down. That is why it is nucleophilic substitution reaction. Substitution go down and nucleophile down. Right. Order is second while because when you write down the rate expression of this reaction. The rate means what? At what speed the reaction is proceeding. That rate depends upon the concentration of this as well as this. Both will depend on that. That is why the order is. So the C H to BR bond does not break. So the C H to BR bond does not break. It will not break. You have for fraction of second you have this stage. That is the intermediate stage. For fraction of second. Then this goes out. This is the first order mean. It depends on only one. Only one of the reactions. This is a very simple. It does not do. See there is no intermediate. Every interval. If SN1 is there then what happens? You will get a factor of time first. And then reaction. So first step means you will get an intermediate. Yes, yes. Understood this. So this is SN2 reaction. We will discuss this in reaction mechanism. So if you get it fine otherwise let it be. We will discuss this. Next slide down. From alkaline right? From anti-hydrogen to eto. Sir what about... It is just a strong reducing agent. Simply a hydrogen attachment. There is nothing to discuss here. That is what I said. It is similar to Wurz reaction. And instead of NAVM saying that is it. Okay. Right on next. From aldehyde and ketone. Preparation yes. Right on this reaction. This is aldehyde or ketone? If you place here hydrogen then it becomes aldehyde. That is all it is. ZHG. With concentrated HCA. The product we get here is R1 CH2 R2. Next reaction is hydrogen. What is the formula of hydrogen? NH2, NH2. Remember NH2, NH2 with H2O2 we are using for alkylolide. Right? Here we are using a base. Keobatch you can use. You can also use NaOH for this. Any base you can use. So with base we use for carbon income. And acid we use, peroxide we use for alkylolide. Right? If you use this base it again gives you R1 CH2 R2. Is that concentrated HCA? Yes. Yeah it is amalgam. Amalgam. Phosphorus with HIE. It is also a strong wood reducing agent. It reduces C11O into CH2. Which one is the wood reducing agent? Red phosphorus with HIE. Both of them together. It is one catalyst, one reagent. Red phosphorus with HIE. There are like multiple steps at once. It is only one. No. It is only one. One step. Last one is which is not that important but you write down. We use diethriol, diethriol in acidic medium. And the second step we use rupture with Ni. All these reactions you see C double bond O converts it to CH2. Right? C double bond O converts it to CH2. The first reaction you must have heard the name. It is cleavage and reduction. No. No. This one is bull kishter. These are important. Very important reaction. This one is mozingo. Yes. Sir, do we know this one? Yes. First two is most important. Do we need to remember the name? Yes. Organic there are many name reactions. We have started already. And name reactions are very important. Mozingo. Mozingo. Gain as CH2. Can't be Kishter. Okay.