 Hello and welcome to the session. Let's discuss the following question. It says prove the following identity where the angles involved are acute angles for which the expression is defined. So let's proceed on to the solution. Let's first simplify LHS which is cosecant A minus sin A into secant A minus cos A. Now cosecant A can be written as 1 upon sin A minus sin A into secant A which can be written as 1 upon cos A minus cos A. Now again taking the LCM we have 1 minus sin square A upon sin A into taking LCM here also we have 1 minus cos square A upon cos A. Now 1 minus sin square A is cos square A upon sin A 1 minus cos square A is sin square A upon cos A. Now cos A gets cancelled so we are left with sin A upon sin A into cos A. Now we will solve the RHS which is 1 upon tan A plus cot A. Now sin A can be written as tan A can be written as sin A upon cos A. So this again equal to taking LCM we have sin square A plus cos square A upon sin A into cos A is further equal to sin A into cos A. Now we know that sin square A plus cos square A is 1 so we are left with sin A into cos A and we have already proved that LHS is equal to sin A into cos A and RHS is also coming out to be sin A into cos A. Hence the identity is proved so this completes the question on this session. Bye for now take care have a good day.