 So the first part of this problem asks us to calculate the solubility of silver one bromide and water. So silver one bromide. So what's the first thing we're going to do? Yeah, always, right at the equation. So silver one bromide, if you don't know it, you know. Now, OK, so a g plus aqueous plus dr minus aqueous, OK? So remember, it asks for the solubility. You could do the ice table if you wanted to, but it's easy enough to just do it this way. So everybody OK with me doing that? So if you look, this is s, this is s, right? So it's going to be s squared there. So s squared is going to equal 5.0 times 10 to the negative 13. And then you can take the square root of both sides here. So we're going to say s equals 5.0 times 10 to the negative 13 square root of the square root. If I answer the solubility of silver one bromide and water, it's going to be 7.1 times 10 to the negative 7 or moles per liter, whatever you like to say. OK, is everybody OK with doing one like that? This, again, is a rehash of one that we've done before. So probably an easier problem.