 Hi and welcome back to the session. I am Asha and I am going to help you solve this question of your NCID textbook which says write the coefficient of x square in each of the following. So in an algebraic expression there are variables and constants. The constant written in the variable is called the coefficient. So the constant which is written before the variable is called the coefficient of that variable. This is the key idea we are going to use in this problem to find the coefficients of x square in each of these problems. Let us now start with the first one which is 2 plus x square plus x. Now when any number is multiplied by 1 then the result is the number itself therefore we can write this expression as 2 plus 1 into x square plus 1 into x. And now we are required to find the coefficient of x square and coefficient is the number on a constant which is written before the variable and the variable here is x square and the number before x square is plus 1. Therefore the coefficient of x square in the above expression is equal to 1. This completes the first part. Now proceeding on to the next one which is minus x square plus x cube. Now this can be written as 2 minus multiplying x square with 1 gives x square. So here multiplying x square with 1 and also x cube with 1. On observing this algebraic expression we find that the constant before x square is minus 1. Therefore coefficient of x square in this algebraic expression is minus 1. This completes the second part and now proceeding on to the third part which is 2 x square plus x. Now we have to find the coefficient of x square in this algebraic expression. So the constant before x square is pi by 2. Therefore coefficient of x square in this algebraic expression is pi by 2. It completes the third part and now proceeding on to the last part which says find the coefficient of x square root over 2 x minus 1. Now on observing this algebraic expression we find here that there is no variable x square. So this can further be written as 0 x square plus root over 2 x minus 1 and here the coefficient of x square is 0. So we have coefficient of x square in this algebraic expression as 0 which completes the last part and hence the solution. So hope you enjoyed this session. Take care and bye for now.