 Okay, so let's try this one, let's try writing a spontaneous redox reaction using these two reaction equations, half-reaction equations, with their electron, our self-attention, okay? So if we look here, both of these are written in the normal form with the electrons being on the left-hand side of the reaction, okay? So hopefully you can see when we combine these two reactions, of course, we're going to need to cancel out those electrons, so one of them has to be flipped around, okay? So let's go ahead and do that and start out with it. So I'm just going to flip the bottom one around, and two plus five equal plus the sign of your potential. So I'm going to erase this middle equation, and we're just going to work with these two equations here. So we have to do the same thing like we have been doing, balancing these equations with respect to the number of electrons that they've got, okay? So this one up here has three electrons, this one has four, so we have to look for a common factor, right? So we're going to multiply this one times three and this one times four, okay? If we do that, it's not like we're going to multiply this time four as well. It's the same potential, okay? So 12 electrons there, 12 electrons there, 15 protons there, 16 protons there. So we have one proton left there, and I don't think there's anything else, right? Okay, so let's write the overall reaction. So I'll write it in the middle, so four plus a proton. So that's your overall, now you're going to want to do the E cell, right? So that's going to be the anode minus, or the cathode minus the anode. So the cell potential, and then, well, what's the oxidizing agent and what's the reducing agent? Let's figure out that, okay? So the oxidizing agent is going to be the nitrate here. Okay, why is that? Because that's the one in the app cell reaction that was donating the electrons, okay? So the reducing agent. So these ones are kind of, you can turn things around, multiply them together. Just remember, don't mess with the actual potential of the cell.