 Hello and welcome to the session. Let us discuss the following question. It says constructed triangle A, B, C in which B, C is 7 cm, triangle A is 60 degrees and altitude through A is 3.7 cm. How many such triangles are possible? So let's now move on to the solution. We'll do the construction and we'll write the steps of constructions. Step is to draw a line segment B, C which has length 7 cm. So this is the line segment B, C and it has length 7 cm. Now the second step is draw equal to 60 degrees. This is the angle C, B, X which is of 60 degrees. Now the third step is draw YBX equal to 90 degrees. So we have drawn the angle YBX which is of 90 degrees. Now the fourth step is draw the perpendicular bisector B, C such that it's BY the point of bisection on B, C. This is the perpendicular bisector of the line segment B, C and it intersects BY at O and D is the point of bisection on B, C. Now the next step is with O as center draw a circle. So we have drawn a circle with center O and OBS radius. Now the next step is from D, mark a point P at a distance 3.7 cm. D we have marked a point P on MN so that this distance is 3.7 cm since we want to have altitude to be 3.7 cm. So we have taken this point such that it is 3.7 cm. Now the next step is draw AA dash through P such that AA dash is parallel to BC where D dash point of intersection with the circle. We have drawn a line segment through P is join AB, AC, A dash B, A dash C. So we have joined AB, AC, A dash B and A dash C. So the required triangles are ABC and A dash BC. ABC, A dash BC are the required triangles. Thus such triangles are possible. So this completes the question and the session. Bye for now. Take care. Have a good day.