 In this video, we will provide the solution to question number 10 from practice exam number two for math 1210, in which case a particle's position at given times are listed below in the following table. So our function is provided in this tabular format. What is the average velocity on the interval zero to five? Well, if the function is a position function, velocity is then the average rate of change will average velocity is then the rate of change of our functions, the average rate of change, much like velocity itself is the instantaneous rate of change of position, the derivative. We're just asking for average velocity. So we need to compute the average rate of change. So we're looking for delta s over delta t as t ranges from zero to five. So this is going to look like s of five minus s of zero over five minus zero. Now the evaluation of the function will come from the table right here. s of five is going to be right here. Notice that time is the second line of this table. So if you take s of five, that's going to be a 20. And if you want s of zero, that's going to be a zero right there. And then in denominator, we just get five minus zero. Simplifying this, we get 20 over five. Or in other words, we get four feet per second, four per minute. Excuse me. That's our unit right there. And that then gives us choice c, that's the correct answer.