 Hello and welcome to the session. Let us discuss the following question. It says we write the following statement with if then in five different ways conveying the same meaning. The statement given to us is if a natural number is odd then its square is also odd. So let us first see the five different implications of the statement if P then Q. First one is P implies Q. The second one is sufficient condition for Q. Third one is P only if Q. Fourth one is Q is necessary condition for P and the fifth one is if not Q then not P. That is not Q implies not P. So let us now move on to the solution. We have to write this statement in five different ways. The first one is P implies Q. Here P is a number is natural which is an odd number and the Q statement is its square is also odd. So P implies Q means a natural number is odd implies its square is odd. So the first way is a natural number is odd implies its is also odd. Let us now see the second way. It is P only if Q that is a natural number is odd only if its square is odd. Third one is Q is necessary condition for P. So the third way is a natural number is not if its square is odd. So for a natural number to be odd it is necessary sufficient condition for Q. So the fourth way is for a square of a natural number to be odd it is sufficient that the number is odd. Another different way is not Q implies not P. Fifth way is if square of a natural number is not odd then the natural number is not odd. These were the five statements conveying the same meaning of the given statement and this completes the question. Bye for now. Take care. Have a good day.