 Hi and welcome to the session let's work out the following question. The question says the radii of circular ends of a solid frustum of a cone are 33 cm and 27 cm and its slant height is 10 cm, find its total surface area. So let this be the solid frustum of cone then the radii are given to be 33 cm and 27 cm slant height is 10 cm. Let us start with the solution to this question. We see that the total surface area of the frustum is given by pi into r1 plus r2 into l plus pi r1 square plus pi r2 square. Now here r1 is equal to 33 cm, r2 is equal to 27 cm and l is equal to 10 cm. So we simply have to put in the values now we have s is equal to that is the total surface area 22 by 7 into 33 plus 27 multiplied by 10 plus 33 square plus 27 square. This is equal to 22 divided by 7 into now 33 plus 27 is 60 this is 10 plus square of 33 is 1089 plus square of 27 is 729. Now this is further equal to 22 by 7 multiplied by 2418 and this is equal to 7599.43 cm square. So our answer to this question is 7599.43 cm square. So I hope that you understood the solution and enjoyed the session. Have a good day.