 Hi and welcome to our session. Let us discuss the following question. The question says two dice are tossed once. Find the probability of getting an even number on the first dice or a total of eight. Let's now begin with the solution. Now two dice can be thrown in six into six ways, and be the event of getting an even number once favorable to this event are 18 and total the probability of E1 is equal to 18 by 36. E2 be the event. Even intersection E2 is equal to these are the outcomes which are section E2 is equal to 3 by 36. Addition plurality probability of even union E2 be equal to probability of even plus probability of E2 minus probability of even intersection E2. Probability of even is 18 by 36. Probability of E2 is 5 by 36 and probability of even intersection E2 is 3 by 46 and this is equal to 20 by 36 and this is equal to 5 by 9. Hence I require answer this 5 by 9. So this completes the session. Bye and take care.