 Hello and welcome to the session. In this session we discuss the following question which says if 8x plus 13y upon 8x minus 13y is equal to 9 upon 7, find x is 2y. First of all let's discuss one result about proportion which is component and dividend. According to this if we have four quantities in proportion that is a is to b is equal to c is to d then a plus b upon a minus b is equal to c plus d upon c minus d. So when we have a upon b is equal to c upon d then on applying component and dividend we get a plus b upon a minus b is equal to c plus d upon c minus d. This is the key idea that we use for this question. Let's move on to the solution now. In the question we are given that 8x plus 13y upon 8x minus 13y is equal to 9 upon 7 and we need to find x is to y. Let this be result 1. So applying component and dividend to 1 we get 8x plus 13y plus 8x minus 13y this whole upon 8x plus 13y minus 8x plus 13y is equal to 9 plus 7 upon 9 minus 7. Now in the numerator 13y and minus 13y cancels in the denominator 8x and minus 8x cancels. So further we get 8x plus 8x that is 16x upon 13y plus 13y that is 26y is equal to 9 plus 7 is 16 upon 9 minus 7 is 2. From here we have x upon y is equal to 16 upon 2 into 26 upon 16. Now 16 cancels with 16 and 2 13 times is 26. So now we have x upon y is equal to 13 upon 1. Therefore we get x is to y is equal to 13 is to 1. This is what we were supposed to find out. So this is our final answer. This completes the session. Hope you have understood the solution of this question.