 Hello and welcome to the session I am Deepika here. Let's discuss the question which says, a system internally measuring 150 cm by 120 cm by 110 cm has 1,29,600 cm cube of water in it. Porous bricks are placed in the water until the system is full to the brim. Each brick absorbs 117th of its own volume of water. How many bricks can be put in without overflowing the water? Each brick brim 22.5 cm by 7.5 cm by 6.5 cm. Now we know that volume of a cuboid is equal to length into breadth into height. So this is a key idea behind that question. We will take the help of this key idea to solve the above question. So let's start the solution. Now the system and bricks have the shape of a cuboid and we have given the internal measurement of the system. That is the length of the system is equal to 150 cm. Height of the system is equal to 120 cm and height of the system is equal to 110 cm. Therefore, volume of the system is equal to 150 into 120 into 110 cm cube because volume of cuboid is equal to length into B into H and this is equal to 198000 cm cube. Now it is given a system has 129600 cm cube of water in it. Therefore volume of water in the system is equal to 129600 cm cube it is given. Now porous bricks are placed in the water and the measurement of each brick is given to us that is the length of the brick is equal to 22.5 cm and its breadth is 7.5 cm and height of the brick is 6.5 cm. Therefore volume of each brick or volume of one brick is equal to L into B into H and this is equal to 22.5 into 7.5 into 6.5 cm cube and this is equal to 1096.875 cm cube. Now each brick absorbs 117th of its own volume of water. Therefore volume of water absorbed by one brick is equal to 1 by 17 into 1096.875 cm cube. Let the total number of bricks be X. Therefore volume of water absorbed by X bricks is equal to upon 17 into 1096.875 cm cube. Now the volume of water left in the system equal to volume of water in the system minus volume of water absorbed by X bricks. Now we know that the volume of water in the system is 129600 cm cube minus volume of water absorbed by X bricks. Which is X over 17 into 1096.875 cm cube. Now as the system is to the brim to the brim. Therefore volume of water left in the system, volume of X bricks to volume of the system. So this implies now volume of water left in the system is 12960 minus X upon 17 into 1096.875 cm cube plus volume of X bricks which is equal to volume of one brick into X. That is X into 1096.875 cm cube and this is equal to volume of the system and which is 18000 cm cube. Now we will solve this equation. So let us take the ICM here this implies 17 into 129600 which is 2200 minus X into 1096.875 upon 17 plus X into 1096.875 is equal to 11800000. So this implies 2200000 minus X into 1096.875 plus 17 into X into 1096.875 is equal to 11800000 into 17 and this implies 2200000 plus now this is X into 1096.875 and this is 17X into 1096.875. So we are left with 16 into X into 1096.875 and this is equal to now 17 multiplied by 11800000 is equal to 3366000 and this implies 16 into X into 1096.875 is equal to 3366000 minus 2200000 and this implies 16 into X into 1096.875 is equal to 31456800 and this implies X is equal to 31456800 upon 16 into 1096.875 and this implies X is equal to 31456800 upon now 16 multiplied by 1096.875 is 17550 so on cancellation we have now so this implies X is equal to 6904 upon 39 and this implies X is equal to 1792.410 therefore we will take X is equal to 1792 and the number of breaks is equal to 1792 and the answer for the above question is 1792 I hope the solution is clear to you. Bye and take care.