 Hello and welcome to the session. In this session we are going to discuss the following question and the question says that the perimeter of a rectangle is 11 by 2 centimeters and its width is 3 by 4 centimeters. Find the length of the rectangle. Let us start with the solution of the given question. We know that perimeter of a rectangle is equal to 2 into length plus width the whole. And we are given that perimeter of a rectangle is equal to 11 by 2 centimeters and its width is given as 3 by 4 centimeters. We have to find its length. Let its length be equal to x centimeter. Now let us put these values in this formula. We get 11 by 2 is equal to 2 into x plus 3 by 4 the whole. Now this is a first degree equation in x. So now we solve it for x. First we open the brackets and we get 11 by 2 is equal to 2 into x that is 2x plus 2 into 3 by 4 which further implies that 11 by 2 is equal to 2x plus 3 by 2. We can also write this equation as 2x plus 3 by 2 is equal to 11 by 2. Now we keep this x term on one side and the constant terms on the other side of the equation and we get 2x is equal to 11 by 2 minus 3 by 2 which implies that 2x is equal to 11 minus 3 whole upon 2 that is 8 by 2. This implies that 2x is equal to 4. Now we divide by 2 on both sides and we get 2x upon 2 is equal to 4 by 2 which implies that x is equal to 2. So we can say that length of rectangle is 2 centimeters. But this is the required answer. This completes our session. Hope you enjoyed this session.