 Hello and welcome to the session. Let us discuss the following question. Question says, choose the correct answer. Integral dx upon sine square x multiplied by cos square x equals a tan x plus cot x plus c b tan x minus cot x plus c c tan x multiplied by cot x plus c d tan x minus cot 2x plus c. Let us now start with the solution. Now we have to find the integral dx upon sine square x multiplied by cos square x. This is further equal to integral of 1 upon sine square x multiplied by cos square x dx. Now we know 1 is equal to sine square x plus cos square x. So we can replace this 1 in the numerator by sine square x plus cos square x. Now this integral can be further written as integral of sine square x dx upon sine square x multiplied by cos square x plus integral of cos square x dx upon sine square x multiplied by cos square x. Now this sine square x will get cancelled by this sine square x and this cos square x will get cancelled by this cos square x. And we get integral of dx upon cos square x plus integral of dx upon sine square x. Now we know reciprocal of cos square x is sex square x. So we can write this integral as integral of sex square x dx plus we can write this integral as integral of cos x square x dx. We know 1 upon cos x is equal to sex x and 1 upon sine x is equal to cos x. So 1 upon cos square x is equal to sex square x and 1 upon sine square x is equal to cos x square x. Now integral of sex square x dx is equal to tan x and integral of cos x square x dx is equal to minus cot x plus c where c is the constant of integration. Now we can further write it as tan x minus cot x plus c. So we get integral of dx upon sine square x multiplied by cos square x is equal to tan x minus cot x plus c. So the correct answer is B. This is our required answer. This completes the session. Hope you understood the solution. Take care and have a nice day.