 Hi and welcome to the session. Let's work out the following question. The question says the horizontal roadway of a bridge AB 12 meter long weighs 56,000 Newton and rests on two supports at its ends. What is the pressure on each support when a lorry of weight 33,600 Newton starting from 8 is at a point two-thirds of the way on the bridge? So let's start with the solution to this question. Now this is how we interpret the question. This is a roadway of a bridge AB 12 meter long. It weighs 56,000 Newton and rests on two supports at its ends, that is, end A and the end B. We have to find the pressure on each support when a lorry of weight 33,600. This is 30,3600 Newton starting from A is at a point two-thirds of the way on the bridge. So let's start with the solution. Length of the bridge that is AB is equal to 12 meter. Weight of the bridge is 56,000 Newton. Therefore, the weight will act at G that is the center of gravity of the bridge such that AG is equal to GB that is equal to half of 12 that is equal to 6 meter and lorry weighing 33,600 Newton at sat 2 by 3 of 12 meter that is 8 meter from point A. Now net R1 and R2 that is this and this are pressure on support A and B respectively. Then R1 plus R2 will be equal to 56,000 Newton plus 33,600 Newton that is equal to 89,600 Newton. Now taking the moment about the point A we will have 56,000 into 6 plus 33,600 into 8 is equal to R2 into 12. This implies that R2 is equal to 56,000 into 6 plus 33,600 into 8 divided by 12 that is equal to 33,600 plus 26,8800 divided by 12 and that is equal to 50400 Newton then R1 will be equal to 89,600 minus R2. This implies 89,600 minus 50400 Newton that is equal to 39,200 Newton hence 39,200 Newton and 50,400 Newton are the pressures on the supports A and B respectively. Now this is what you are supposed to find in this question. I hope that you understood the solution and enjoyed this session. Have a good day.