 Hi and how are you all? The question says solve the inequality for real x. Now here we need to find the value of x and the inequality given to us is x by 4 is less than 5x minus 2 divided by 3 minus 7x minus 3 divided by 5. Now on multiplying both the sides on each term by 60 that is the LCMO 4, 3 and 5 we have 15x is less than 20 bracket 5x minus 2 minus 12 bracket 7x minus 3. Now on removing the brackets we have 15x is less than 100x minus 40 minus 84x plus 36. After simplification we have 15x is less than 16x minus 4. Subtracting 16x from both the sides we have 15x minus 16x is less than 16x minus 4 minus 16x. After simplification we have minus x is less than minus 4. Now on multiplying both the sides by minus 1 and following the rule that when both sides of the inequality are multiplied by same negative number then the sign of inequality changes. So now we have x is greater than 4 and for real x the solution set consists of all real numbers that are greater than 4 and hence the solution set is equal to in an open interval 4 to infinity. So this is our required answer.