 Hello and welcome to the session. In this session, we will discuss a question which says, first part, Adam spent 4 by 7 hours and Andrew spent 16 by 21 hours doing homework. How much more time did Andrew spend in doing homework? So in fact evaluate, we know this A here, A is equal to 145.9 and B is equal to 362. Now let us start with the solution of the given question. Now here it is given that Adam spent 4 by 7 hours doing homework and Andrew spent 16 by 21 hours doing homework. Now let us find the difference in hours. So here the difference in hours is equal to 16 by 21 minus 4 by 7. Now 16 by 21 and 4 by 7 are unlike fractions. So first we make them like fractions. For this, first of all let us find LCM of the denominators that is the LCM of 21 and 7 which is equal to 7 into 3 which is equal to 21. Now here the least common denominator is 21. Now for converting 7 into 21 we will multiply it with 3. So reflection 4 by 7 will be equal to 4 into 3 upon 7 into 3 which is equal to 12 upon 21. Now we have converted 16 by 21 and 4 by 7 into like fractions that is the fractions 16 by 21 and 12 by 21. So now the difference in hours will be equal to 16 by 21 minus 12 by 21. Now this will be equal to 12 4 upon 21 which is equal to now 16 minus 12 is 4 upon 21 hours. Therefore Andrew spent 4 by 21 hours more in doing homework. Second part given A is equal to 145.9 B is equal to 362 and we have to find B minus A. Now substituting the values of B and A we get B minus A is equal to 362 minus 145.9. Now here you can see that there is only one digit in the decimal part of 145.9. So we will put 1 here in the decimal part of 362. So we will subtract 145.9 from 362.0 and subtracting we get 216.1 greater than 145.9 in the answer. So B minus A is equal to 216.1 and this is the solution of the given question. That's all for this session. Hope you all have enjoyed this session.