 Welcome to the recitation. Let us discuss the current question. The question says that the resultant of two unlike parallel forces of 15 Newton and 10 Newton acts along a line at a distance of 12 centimeters from the line of action of smaller force. Find the distance between the lines of action of the two given forces. Let us now begin with the solution. Let the unlike forces which the resultant passes. This resultant is equal to 10 Newton. That is, we externally see by P into 18 is equal to BC into 10. BC is equal to 12 centimeters. So AC is equal to 12 into 10 divided by 3 centimeters. Now we will find AB to BC minus AC. BC is equal to 12 centimeters and AC is equal to 6 and 2 by 3 centimeters and 1 by 3 centimeters.