 In this video we are going to look at a few coordination compounds and try naming them based on the rules that we have just studied. So here is the first coordination compound and the first rule is that we name the cation before the anion. Now in this particular compound which is the cationic and anionic part, the coordination entity is the cationic part and the counter n is the anionic part. So obviously chloride part would be at the end of the name. Okay so let's see how to name this particular coordination entity. Now within a coordination entity we will first have to name the ligands and how many ligands do we have? We have two ligands ammonia and carbonate. So when it comes to ligands we know that we have to name them alphabetically right? Now ammonia is a neutral ligand and its name is amine and CO3 is an anionic ligand and its name is carbonate. But since it's an anionic ligand we know that the name should end with an O right? So it will be carbonate DO. Now which among them will take precedence? Well alphabetically ammonia will come before carbonate and how many ammonia ligands are there? Five. So the prefix for that would be penta and how many carbonate ligands are there? Just one. So that would be carbonate DO. So within the coordination entity if I simply look at the naming of the ligands it would be penta amine carbonate DO. So this is the ligand part, perfect. Now after the ligand we need to go to the metal right? Now since it is a cationic complex the name of the metal would be same as the metal itself that is unlike the anionic complex where the name of the metal ends with an 8 we have no complications in the cationic complex. So the name of the metal would be cobalt, correct? If it was an anionic complex it would be cobaltate and what's the next thing that we need to do? We need to write the oxidation state of the metal right? So for that if you assume that X is the oxidation state of cobalt and you have neutral ammonia so it would be 0, carbonate is minus 2 and chlorine is minus 1 overall charge is 0. So that would give X is equal to plus 3. So therefore the oxidation state of cobalt is 3. Now remember there is absolutely no spacing to be given between the ligand and the metal ion right? So here is the metal, so no space to be given between these two. So this is the entire cationic part and now we need to come to the anion which is the chloride ion so that is pretty straight forward it would be chloride. So the final name of this particular compound is pentamine, carbonate, cobalt chloride. So let's look at one more compound. So here is the second compound. So let's try naming this okay? Here again the first rule is to name the cation and then the anionic part. Here again the coordination entity is the positively charged part and the counter ion chloride ion is a negatively charged part. So what do we need to do? We have to name the cation first which means we have to look at the coordination entity first. And within the coordination entity we know that we need to look at the ligands first and then the central metal atom okay? So let's look at the ligands. How many ligands do we have here? We have three ligands, two ammonia which means we have a main, one Cl which is an anionic ligand that means the name would end with chlorido correct? Because we will add an O at the end of anionic ligands. And now again we have NH2CH3 which is neutral again. So this is nothing but methanamine. So these are the three ligands that we have and which one would take precedence? Well that would depend on the adorbital order right? So first comes ammonia, then comes chlorine and then comes methane amine. So this is the order in which we will have to name the ligands. Now how many ammonia ligands are there? Two. So the prefix we add would be diamine. How many chloradions? Just one and again only one methane amine group. So let me write the name here that would be diamine. Next one is chlorido. So chlorido and methane amine would be written in brackets. Methane amine. Okay so we are done with the ligands part and now we need to look at the central metal right? Since it is a positively charged complex the name of the metal would be exactly same as the metal itself. So that is platinum. If it is an anionic complex the name would be platinate correct? Now what is the oxidation state here? Let's quickly look at the oxidation state x plus 2 into 0 plus minus 1 of chlorine again plus 0 plus minus 1 of chlorine and total charge is 0. So x would be plus 2. That means the oxidation state of platinum is 2. So this is the cationic part. So we are done with the cationic part and finally we need to name the anionic part which is very simple which is chlorine and we need to leave a space between the anionic and the cationic part so let me move it here chloride. So the name of this particular compound is diamine, chlorido, methane amine, platinum to chloride. Alright, let's look at another simple coordination compound. So let's first try to identify the cation and then the anionic part. Now interestingly in this case our counter ion is positively charged and our coordination entity is negatively charged okay? Since we named the cation first we can write the name of the cation directly here which is now we need to look at the anion and anion is a coordination entity. So first we will begin by naming the ligand and then the central metal atom. So the ligand is chlorine and we know that since chlorine is a negatively charged ligand or an anionic ligand the name has to end with O so that would be chlorido. We have only one type of ligand here which is chloride group and how many are there? We have four. This would be tetra, chlorido, simple right? Now let's look at the central metal. When it comes to the central metal we know that the central metal atom here is in an anionic complex. In such cases the name of the metal atom would end with an 8. If it was in a positively charged complex then the name would be copper but since it is in a negatively charged coordination entity the name would be cubrade. In the next step we need to write the oxidation state of copper. So what is the oxidation state here? Okay let's quickly calculate that that is 2 into plus 1 of potassium and let X be the oxidation state of copper and you have 4 into minus 1 of chlorine group and overall charge is 0. So that means X is nothing but plus 2. So copper here has plus 2 oxidation state. A very simple example right? So the final name would be potassium tetra, chlorido, cubrade 2.