 Hi and welcome to the session. I am Deepika here. Let's discuss the question. The question says whether the following is in AP, if they form an AP, find the common difference D and write three more terms, 3, 3 plus root 2, 3 plus 2 root 2, 3 plus 3 root 2 and so on. We know that the given list of terms A1, A2, A3 so on forms an AP if the difference of a term and its preceding term is always constant. This constant is called the common difference of AP. We will use this key idea to solve our question. Let's start the solution. Our given list of terms is 3, 3 plus root 2, 3 plus 2 root 2, 3 plus 3 root 2 and so on. We have A2 minus A1 is equal to 3 plus root 2 minus 3, which is equal to root 2. Now A3 minus A2, 3 plus 2 root 2 minus 3 plus root 2, this is equal to root 2. Again A4 minus A3 is equal to 3 plus 3 root 2 minus 3 plus 2 root 2, which is equal to root 2. That is, Ak plus 1 minus Ak is the same every time, that is it is constant. Hence 3 plus root 2, 3 plus 2 root 2, 3 plus 3 root 2, so on, forms an AP with common difference, D is equal to root 2. The next three terms are 3 plus 3 root 2 plus root 2, which is equal to 3 plus 4 root 2, 3 plus 4 root 2 plus root 2 is equal to 3 plus 5 root 2, next is 3 plus 5 root 2 plus root 2 is equal to 3 plus 6 root 2. Hence our answer for the above question is, yes, the given list of terms form an AP with common difference D is equal to root 2 and the next three terms are 3 plus 4 root 2, 3 plus 5 root 2 and 3 plus 6 root 2. I hope the question is clear to you. Bye and have a good day.