 There are these two circles, which meet at a point, which are, you know, that Klein bottle is really a band connects, a band connects some of two mobius bands, right? And what you did is get rid of one of the mobius bands. And so, you know, yeah, no, I see what you're saying. Yeah, then, right, you should think of the Klein bottle as an annulus connects some RP2, yeah. So it's connects some of the torus, yes, OK. So, yes. Yeah, yeah, yeah, yeah, yeah, yeah, sure, right. I mean, there's the, you know, I mean, if you've seen, some of you've seen me talk about this stuff before, it's actually quite fun to think about what happens. You know, what do I say? You know, with a little care, you can see the kind of, you know, octahedral axiom of triangulated categories come out nicely, and a key part of that is, you know, the fact that, you know, in the octahedron story, there are, you know, an octahedron with four faces that are commutative, which are exact triangles. The complementary faces are commutative triangles. The reason the triangles are commutative are because of this fact. This is saying that something, the two maps are, the composite of two maps is a third map. Anyway, there's an amusing story like that. Yes, Vivek. Well, you have to count instantons on the courtesans. I mean, you're meeting them all the time. And so far, you don't, they don't come up yet. Yeah, eventually, I mean, eventually you see them. I don't know, I haven't used it yet. I mean, yeah, well, you know, at some level, well, you know, it won't speculate on that. Yes. Well, I mean, there are reasons to expect it, and then you can prove it just using the exact triangle, actually, that's the safest way to prove it. I mean, so, if you look at just, you know, you have to figure out what a pair of pants does, for example. Now, if you think about just what happens on the level of representation varieties, so we're looking at base representation varieties. For the on knot, it's a two-sphere. For the on link of two components, it's S2 times S2. And the actually representation variety of the pair of pants itself, if you think about it, the fundamental group of the complement of the pair of pants is just Z. So it's a two-sphere as well. So on the level of representation varieties, you're just getting the inclusion of S2 as the diagonal in S2 times S2. And that's, you know, that sort of the Frobenius algebra construction of the map and Habana Fomology. Now, you have to check that instantons don't contribute to that, that there's no other contributions. And in fact, there are instantons there. So they just happen to cancel. So it's not, you know, that's why the exact triangle is a bit safer way to do the computation because then you know, you kind of understand where the cancellation comes from. And in fact, an interesting thing to do is to chain just to, you know, do instanton homology with local coefficients. So it turns out that once you introduce the knots, the fundamental group, if there's just one component, fundamental group of the space of connections with a knot is Z plus Z instead of Z. So there's still an interesting Z to play with, which you can use to twist the coefficients. And the twisted coefficient things actually see that there's sort of two instantons there and they see them and then you get the leap perturbation of Habana Fomology come out. So there's, you know, there's a lot more stuff under this rug. But I hope I convinced you that it's worth trying to pick it up. Yes. Oh, well, that's another long story. So the, so, which goes briefly like this. So Floor actually defined a knot invariant for, you know, an instanton knot invariant a long time ago and what his construction is, you're going to take the three torus with W2 non-zero, drill out S1 times D2 in it, stick your knot complement in it in such a way that the ciphered surface of the knot completes that punctured torus. That turns out, so that, you know, converts your knot into a three-manifold with well-defined floor homology, that's not floor homology. So it turns out that that more or less is isomorphic to the one that we define this way, but it can be studied using sutured manifold theory and then using sutured manifold theory and a lot of work. You know, so you're kind of mimicking some of the stuff that Gijini and, sorry, it's too early, not enough coffee. Youhash, Yini, et cetera did, you can eventually show that that instanton knot floor homology detects the unknot. So it's sort of this huge machine that you need for that, and eventually you can see the Havana story. By the way, I should say that there's now a sort of non-instanton proof that Havana homology detects the unknot, which uses a version of Hagar floor homology due to Nate Allen. Yeah. Anything else? Okay.