 Hi and welcome to the session. Let's discuss the following question. It says, in how many ways can a team of three boys and three girls be selected from five boys and four girls? Before solving this question, we should know the theory of combination which says that our objects from n objects can be selected our ways. Also know the fundamental principle of counting which says that event A occurs in, event B occurs in and event A and B occur in into n ways. Knowledge will work as the key idea. Now move on to the solution. Now we have to select three boys and three girls from five boys and four girls. The number of ways to select three girls equal to four C3 which is equal to four factorial upon three factorial into one factorial which is equal to four and the number of ways to select three boys from five boys is equal to five C3 which is equal to five factorial upon three factorial into two factorial. Now five factorial can be written as five into four into three factorial upon three factorial into two factorial. Now three factorial gets cancelled with three factorial and two into two is four and it is equal to five into two that is ten. This is why the theory of combination that is our objects from n objects can be selected in n c r ways. Now we have to form a team of three girls and three boys. So the total number of ways three boys equal to four into ten number of ways to select three girls into the number of ways to select three boys. This is why fundamental principle of counting we discussed in the key idea and it is equal to 40. Hence the answer is 40 and this completes the question. Bye for now take care have a good day.