 Hello and welcome to the session I am Deepika here. Let's discuss the question which says, it dies number in such a way that its spaces show the numbers 1, 2, 2, 3, 3, 6. It is thrown two times and the total score in two throws is noted. Complete the following table which gives a few values of the total score on the two throws. Numbers in first throw 1, 2, 2, 3, 3, 6. Numbers in second throw 1, 2, 2, 3, 3, 6. 1 plus 1 is 2, 2 plus 1, 3, plus 1, 3, 3 plus 1, 4, 3 plus 1, 4, 6 plus 1, 7. 1 now 6 plus 6 probability that part 1 even part 2 6. Number of outcomes favorable to E. Number of all possible at the solution have to complete the given table which gives a few values of the total score on the two throws. Now given table is we will complete these. Now 1 plus 2 is 3, 2 plus 2 is 4, 2 plus 2, 4, 3 plus 2, 5, 6 plus 2, 8. Again 1 plus 3, 4, 3 plus 3, 6, 3 plus 3, 6 and 6 plus 3, 9. 1 plus 3, 6, 3 plus 3, 6. According to this table that the total therefore the outcomes event is number of outcomes favorable possible outcomes which is 36 equal to 1 upon 2. Part 1 is 1 that is the probability that this score is even is 1 by 2. That is the total event B by event B upon 9. Hence the answer for upon 9 probability that the total is 12. This implies that the event is equal to number of outcomes favorable to event E. Number of probability that the total score is at least.