 Hello and welcome to the session. In this session, we are going to discuss the following question and the question says that suppose vector P is equal to the ordered pair 2,3 and vector Q is equal to the ordered pair minus 1, minus 6. First part, draw a vector diagram to illustrate vector P minus vector Q. Second part, find vector P minus vector Q in component form. Let us start with the solution of the given question. Here we are given vector P and vector Q. In the first part of the question, we have to draw a vector diagram to illustrate vector P minus vector Q. So, let us first draw vector P. Vector P is given by the ordered pair 2,3. So, we take any initial point and we move two units to write 1, 2 and three units up 1, 2, 3 and we reach this terminal point with upward direction. Now vector Q is given by the ordered pair minus 1, minus 6. So, we take any initial point and move one unit to left and six units down 1, 2, 3, 4, 5, 6 and we reach this terminal point with downward direction. We have to represent vector P minus vector Q which is equivalent to vector P plus of minus of vector Q where minus of vector Q is opposite or negative of vector Q. Thus minus of vector Q will have same magnitude as Q but will be in opposite direction. Minus of vector Q will be equal to minus 1 into ordered pair minus 1 minus 6 which is equal to the ordered pair minus 1 into minus 1 that is 1 minus 1 into minus 6 that is 6. So, minus of vector Q is equal to the ordered pair 1, 6. So, at terminal point of vector P, we draw minus of vector Q. Here we draw minus of vector Q such that it is parallel to vector Q. Now, treating terminal point of vector P as initial point of minus of vector Q, we move one unit right and six units up. So, here we have moved one unit to the right and now six units up that is 1, 2, 3, 4, 5, 6. We reach this terminal point with upward direction. Now we joined initial point of vector P with terminal point of minus of vector Q. So, by triangle rule, this represents resultant vector given by vector P plus minus of vector Q which is equal to vector P minus vector Q. Now, we move on to the second part of the question which says find vector P minus vector Q in component form. Now, we find vector P minus vector Q in component form. Now, vector P is given by the ordered pair 2, 3 and vector Q is given by the ordered pair minus 1, minus 6. So, vector P minus vector Q will be equal to the ordered pair 2, 3, minus of the ordered pair minus 1, minus 6 which is equal to the ordered pair 2, minus of minus 1, 3, minus of minus 6 which is equal to the ordered pair 2 plus 1, 3 plus 6 and this is equal to the ordered pair 3, 9. This implies that vector P minus vector Q is given by the ordered pair 3, 9. Thus, we say that component form of vector P minus vector Q is given by the ordered pair 3, 9 which is the required answer to the second part of the question. This completes our session. Hope you enjoyed this session.