 Hello and welcome to the session. Let us understand the following problem. Find the equation of line joining 1, 2 and 3, 6 using determinants. Now let us write the solution. Let p x, y be any point on the line joining a with vertices 1, 2 and b with vertices 3, 6. Now let us draw the figure. We have point a as 1, 2 and point b as 3, 6. Now let us draw this line. Now let us take any point p with vertices x, y. Now here a, p, b, r, collinear. So it implies area of triangle a, p, b is equal to 0 because a, p, b are collinear, which implies half into 1, 2, 1, x, y, 1, 3, 6, 1 is equal to 0, which implies half into 1, 2, 1, x, y, 1, 3, 6, 1 is equal to 0, which implies this will be 7 becomes 0. So we are left with 1, 2, 1, x, y, 1, 3, 6, 1 is equal to 0, which implies 1 into y minus 6 minus 2 into x minus 3 plus 1 into 6x minus 3y is equal to 0, which implies y minus 6 minus 2x plus 6 plus 6x minus 3y, which is equal to 0. Now this gets cancels. So we are left with commanding the light terms minus 2x plus 6x gives 4x and y minus 3y gives you minus 2y, which is equal to 0, which implies 2y is equal to 4x, which implies y is equal to 2x. Hence, y is equal to 2x is the required equation of this weight line. I hope you understood the problem. Bye and have a nice day.