 Hi and welcome to the session I am the picker here. Let's discuss the question. Find the point on the x-axis which is equidistant from 2-5 and minus 2-9. So let's start the solution. Let this 5 and b minus 2-9 be the given point at 0. So a point on the 5-square is equal to x plus 2-square equal to 81 minus 25. This implies 2 minus 7. So the required answer for the above question is minus 7-0. This is the point p which is equidistant from a and b. I hope the question is clear to you. Mine enjoy yourself.