 Hello and welcome to the session. I am Deepika here. Let's discuss a question which says find the area of a quadrant of a circle whose circumference is 22 centimeter. Let us first recall the formula for area of a sector of a circle. Now if r is the radius of the circle the angle of the sector in degrees then of the half angle theta is equal to theta upon 360 into pi r square. So this is the key idea behind our question. We will take the help of this key idea to solve our question. So let's start the solution. For solving this problem first of all we find the radius of the circle whose circumference is 22 centimeter. Now we know that circumference of the circle equal to 2 pi r where r is the radius of the circle. Now circumference of circle is given to us 22 centimeter or this is equal to 22 centimeter is equal to 2 into 22 by 7 into r or r is equal to 22 into 1 by 2 into 7 upon 22. So on cancellation we have r is equal to 7 by 2 centimeter. Hence the radius of the circle is 7 by 2 centimeter. Now again we want to find the area of a quadrant of a circle then the angle of the sector at the center is 90 degree. Now we want to find the area of a quadrant of a circle whose radius is 7 by 2 centimeter AOV is 90 degree that is the angle of the sector is 90 degree. So area of the quadrant of a circle is equal to theta upon 360 into pi r square. Now theta is equal to 90 degree. Therefore the area of a quadrant of a circle is equal to 90 upon 360 into take pi as 22 by 7 into 7 by 2 into 7 by 2 centimeter square and this is equal to on cancellation we have 11 into 7 upon 4 into 2 centimeter square or this is equal to 77 upon 8 centimeter square. Hence the area of a quadrant of a circle whose circumference is 22 centimeter is 77 upon 8 centimeter square and this is our answer. I hope the solution is clear to you. Pi and take care.