 Hello friends and how are you all doing today? The question says a bag contains 30 tickets numbered from 1 to 30 five tickets are Drawn at random and arranged in a second order find the probability that The third number is 20. So let's proceed with the solution now here Five tickets out of 30 can be drawn in 30 C5 Ways right so the required probability We equal to 19 C2 into 10 C2 divided by 30 C3 Because since the third ticket must be 20 in number It means two tickets are less than 20 and two are more than 20 right, so One solving we have it as 19 into 18 into 10 into 9 into 120 divided by 2 into 2 into 30 into 29 into 28 into 27 into 26 Which on simplifying gives us the answer as 285 upon 5 to 7 8 right, so hope you understood this concept well and Enjoy solving this question to have a nice day ahead You