 Hi, and how are you all today? Let us discuss the following question. It says, find the value of other five trigonometric functions. The value of tan x here given to us is minus 5 by 12 and it's also given that x lies in the second quadrant. Let us start with our solution. Now here the value of tan x is given to us as minus 5 by 12. Therefore, cot x will be minus 12 by 5, right? Now we know that 1 plus tan square x is equal to 6 square x, right? So we can find out the value of 6 square x by substituting the value of tan x in this identity and our answer comes out to be the square root of 169 by 144 and that is equal to 13 by 12. Now we need to think of a sign since it's given to us that x lies in the second quadrant. So therefore, the value in second quadrant will be negative. So we have minus 13 by 12, which also gives the value of cot x as minus 12 by 13. Further to this, we know that sin x is equal to tan x cos x. So let us substitute the value of tan x and cos x and on doing so we have the value of sin x as minus 5 by 12 multiplied by minus 12 by 13. That gives us the value of sin x as 5 by 13. That is positive. Now we can find the value of cos x as 13 by 5, right? So the solution comes out to be the values which we have found out that is cot x, sin x, sin x, sin x and cos x. And all the values were minus 12 by 5, minus 13 by 12, minus 12 by 13, 5 by 13 and 13 by 5 respectively. So this ends the question that was given to us. I hope you enjoyed the session and do remember you need to find all the other five trigonometric functions. Bye for now.