 Welcome to the session. Let's discuss the following question. The question says solve the differential equation y plus x into dy by dx equals to y minus x. Let's now begin with the solution. We have to solve the differential equation y plus x into dy by dx equals to y minus x is dy by dx, dy by 2v minus 1 divided by v plus minus v squared minus v divided by v plus equal to minus 1 into 1 plus v squared divided by v plus minus 1 by x equals to minus into integral of y, which we get to integral of 1 by x with respect to x is minus log. As v squared is positive, so is v squared plus 1, so we don't need to write mod over here. Thus we have log 1 plus v squared equals to minus log x plus c. Now v is equal to y by x plus y squared by x squared plus tan inverse y by x equals to minus log x plus c. This implies 1 by 2 log x squared plus y squared minus 1 by 2 into 2 log 1 by 2 into log x squared plus y.