 Hi and welcome to the session. I am Deepika here. Let's discuss the question. Move that the function I have given by fx is equal to x square minus x plus 1 is neither strictly increasing nor strictly decreasing on an open interval minus 1 to 1. So let's start the solution. Given fx is equal to x square minus x plus 1, therefore, f dash x is equal to 2x minus 1. Now, f dash x is equal to 0 implies x is equal to 1 by 2. Hence, x is equal to 1 by 2 divides the interval minus 1 to 1 into 2 disjoint intervals that is minus 1 to 1 by 2 and 1 by 2 to 1. Now for x less than 1 by 2, f dash x is less than 0. This implies f is strictly decreasing in minus 1 to 1 by 2. Now for x greater than 1 by 2, after x is greater than 0, this implies f is strictly increasing in 1 by 2 to 1. Now, f is strictly decreasing in the interval minus 1 to 1 by 2 and it is strictly increasing in the interval 1 by 2 to 1. So on the entire interval minus 1 to 1, it is neither strictly increasing nor strictly decreasing because f dash x does not have the same sign on an entire interval minus 1 to 1. Hence, f is neither strictly increasing nor strictly decreasing minus 1 to 1. Hence, proved. I hope the question is clear to you. Bye and take care.