 Hello friends and how are you all today? The question says, Construct a triangle ABC in which BC is equal to 7 centimeters, angle A is equal to 60 degrees and altitude through A is 3.7 centimeters. How many such triangles are possible? Now here in this question, what I will do is I will write down the steps of construction for you and show you how it is actually done. Right? First of all we need to draw a line segment BC equal to 7 centimeters. Like this. Now on one side of BC we need to make an angle let's say CBX equal to 60 degrees. And now we need to draw this. Now here we have drawn angle CBX equal to 60 degrees on one side of BC. Now the third step is to draw a line BY perpendicular to BX. Now here this is BX we need to draw BY which is a line perpendicular to BX like this. Now the fourth step is to draw perpendicular bisector PQ of the line segment BC. Let it intersect BY at the point O. Now here we need to draw a perpendicular bisector of BC which will intersect BY at O. And remember how to draw a perpendicular bisector we need to take radius more than half of BC, draw two arcs above and below BC and then taking C as the center we need to draw another two arcs above BC and below BC which will intersect the previous arc at point P and Q. So this is the required perpendicular bisector PQ that is a perpendicular bisector of BC intersecting BY at point O. So let this point be point O. Now the fifth step is taking O as center and OB as radius we need to draw the alternate segment to the angle 60 degree of the circle. So here taking O as center and OB as radius we need to draw a segment which is alternate to the 60 degrees like this. Now from the midpoint M of BC cut MN 3.7 centimeter on PQ. So we have written the step also and now we will be doing it. Now this is 3 centimeter and this point will be N. Now what we need to do is we need to draw a perpendicular line through N to PQ intersecting the segment of the circle at two points one will be A and one let be A dash. Let me write down the step also for you and then we need to join these points also. So we have one point is first of all we need to draw a perpendicular line through N that will be this is a perpendicular line which are intersecting at A and A dash and then we need to join AB AC A dash B and A dash C. So we have AB and AC and then we have let it be from a different color A dash B and A dash C. And finally thus triangle ABC and triangle A dash BC are the required triangles. And one thing more was asked from us in the question we were asked how many such triangles are possible. So we can see here we have drawn two triangles ABC and A dash BC. So there are we conclude that they can be two such triangles. Right so this completes the session hope you understood whole construction well do it very neatly and take care have a nice day.