 Let us discuss the following question. The question says differentiate with respect to x tan inverse square root of 1 plus sin x plus square root of 1 minus sin x divided by square root of 1 plus sin x minus square root of 1 minus sin x. Now begin with the solution. Let y is equal to tan inverse square root of 1 plus sin x plus square root of 1 minus sin x divided by square root of 1 plus sin x minus square root of 1 minus sin x. Let us consider square root of 1 plus sin x. Now 1 is equal to sin square x by 2 plus cos square x by 2 and sin x is equal to 2 sin x by 2 cos x by 2 is equal to square root of sin x by 2 plus cos x by 2 whole square. And this is equal to x by 2 plus sin x by 2 x by 2 for zero less than root divided by 2 sin. Now we can write also. So this completes the session. Bye and take care.