 Okay, so let's do this one. This one just says predict the products of the following reaction and it gives you cyclohexamol and phosphorus, tribromide, and ether. So since it says predict the products, all you really need to do is say what is made. Okay? So if you can do that without thinking about the mechanism, then you're cool. Okay? So I'm going to write what the product is. So if you would have gotten that, you would have gotten that normally because you know the mechanism, you know. So if you don't know the mechanism, it's going to be very difficult to do this unless you just memorize a bunch of reagents, you know, and memorize what they do. It's a terrible way to do things. Okay? So it's just not a good way to do things. Okay? So we're just going to figure out, well, what is the mechanism? Okay? So remember whenever you're doing mechanism, you're going to find the nucleophile and you're going to find the electrophile. So we talked pretty extensively about this particular one in class and we said, well, first off, right, nucleophiles are going to be where the lone pairs are or where the pi bonds are. Okay? So we look over here and we see lone pairs all over here. Lone pairs, lone pairs, lone pairs. So a lone pair that are two. We know none of those lone pairs are nucleophilic because they're on those halogens. But we also know that oxygen, it likes phosphorus. So phosphorus is oxafilic. So that gives us a really big clue as to what's going to happen. So the first step is going to be the attack of the oxygen onto the phosphorus. Okay? And you can think of a complex being formed if you want to. Or you can just think, we're going to break out that from, it's probably the easier way for you all to think about it right now. Phosphorus there. We haven't lost our hydrogen so there's going to be a positive charge coming. But we have lost the bromine so there's still only three bonds to phosphorus so the charge isn't going to change today. The other thing you want to remember, there's no brawl zero charge here. So there's going to be no brawl zero charge here. So then the next step, of course, is just going to be the acid to attack of the bromine on this complex. Okay? It's a big structure. Just like Cassandro was saying with mechanisms, we probably want to put the other portion just so we can account over that mechanism before. But if you're having trouble, learn it because this is a good one to remember because it takes off our alcohols. You can do the same thing except take it to an alkyl fluoride if you use thionyl fluoride. And of course there's recordings of those too. So check it out.