 Hello and welcome to the session. Let's work out the following question. It says prove the following identity where the angles involved are acute angles for which the expression is defined. So let's now move on to the solution and let's start with NHS. NHS is cosecant theta minus cos theta whole square. Now this can be written as 1 upon sin theta minus cos theta upon sin theta whole square because cos theta is cos theta upon sin theta cosecant theta square is 1 upon sin theta so this is equal to 1 minus cos theta whole square upon sin square theta. Now again this is equal to 1 minus cos theta whole square upon sin square theta which can be written as 1 minus cos square theta then this is equal to 1 minus minus cos theta whole square upon 1 minus cos square theta can be written as 1 minus cos theta into 1 plus cos theta. Here we have used the formula of a square minus b square and in this case a is 1 and b is cos theta. So 1 minus cos theta gets cancelled with one of the 1 minus cos theta and we are left with 1 minus cos theta upon 1 plus cos theta and this is what we have to prove. Hence LHS is equal to RHS. So this completes the question on the session. Bye for now. Take care. Have a good day.