 Okay, so let's do one of these problems. This is converting KdQ to delta G. So this one says, for the following reaction, alpha ketoglutarate plus NAD plus CoASH goes to succinyl CoA plus carbon dioxide plus NADH plus proton. If the KdQ for this reaction is 4.6 9-2 times 10 to the third, calculate the delta G for this reaction and decide whether this reaction will be favorable or unfavorable at these conditions and which side of the equilibrium will the reaction lie on? So the first thing we want to do in this reaction this problem is what? Remember the equation. Okay, so do y'all remember it? What is it? Delta G equals negative RT ln KdQ. So remember in this one, oh I didn't read it, but it said it wanted it in kilocalories, which is why I gave us the R for calories. Remember these R's will always be given to you. Any constants will be given to you. It's not something you need to remember. The thing you want to remember though is if it asks for Joules or kilojoules you're going to use the 8.31 for Joules per mole kelvin. Okay, so and the other thing this constant tells us is what? That the temperature has to be in what? Kelvin. So since Celsius so we have to add 273 to it. So what do we get? 298 kelvin, okay. So now we got that, we got that, we got that, so now it's just a plug and choke problem. So negative R, so I'm going to write this all out so we can see the cancellation. Okay, so I usually will do these backwards. I'll do this part first. ln of 4.692 times 298 times negative 1.987. Okay, so we want this to three significant figures, but the calculator gives us a bunch of numbers. So we're going to just write down some of them and then we'll figure it out later. So I put negative 5,005 kelvin per mole, but we want to convert this to three significant figures and to kilocalce. Okay, so remember this is per 1 mole. How many cows are going to kill a cow? A thousand. So when we do that we're going to take this to negative 5.005 kilocalce but to take that to three significant figures it's going to be negative 5.01 kilocalce per mole. Okay, so that is what delta G is. Okay, so would this be a favorable or unfavorable reaction? Favorable what? Negative delta G. So that means favorable. So that kind of leads into our next question. So which side of the equilibrium does this reaction lie on the left or on the right? Right side. The right. Okay, so delta G negative favorable. Okay, hexagonic. Any questions on this one? Wonder.