 We know that alkyl halides react with sodium metal in dry ether to form hydrocarbons with double the number of carbon atoms as that was present in the alkyl halide or initial reactant right. Now this reaction is called Wode's reaction. Now if you replace one of the alkyl halides with an aryl halide in that case we get the product which is an alkyl arene and this reaction is called Wode's fatigue reaction. So here you have a new cc bond that is being formed between the alkyl group of the haloalkane and the phenyl group of the haloarene. Now finally if you replace two alkyl halides with two aryl halides in that case we obtain a diphenyl as the final product and this reaction is called a fatigue reaction. As you can see these are all derivatives of the Wode's reaction. Now if you look at the mechanism we know that Wode's reaction has been proposed to occur via two different mechanisms. One is a free radical mechanism and the other one is the ionic mechanism and something similar can be extended to these reactions as well. So if you talk about a free radical mechanism here you can see that the sodium metal donates an electron to the alkyl halide and results in the formation of an alkyl radical. Now similarly the cx bond in the aryl halide also breaks up to form a phenyl radical and corresponding salt. Now this phenyl radical can combine with the alkyl radical to give us the alkyl arene as shown here. Now you can obviously see the disadvantage of this reaction right? Just like Wode's reaction you will end up with many different products here or a mixture of products. For example the alkyl radical can combine with another alkyl radical to give us a different product which is RR instead of the alkyl arene that is a desired product. Now if you look at the ionic mechanism we can see that here sodium metal again donates an electron to the alkyl halide and results in the formation of an alkyl radical. But in the second step this alkyl radical accepts another electron from the sodium metal to form a carbanion as you can see here. Now this carbanion can attract the aryl halides to give us the substituted product. Now this mechanism carries an inherent doubt that aryl halides are not very reactive towards nucleophilic substitution reactions right? Now because of the inherent problem of forming a mixture of products these reactions are not the preferred way to produce alkyl arenas in laboratories. In fact we have come up with many different much more efficient ways of synthesizing alkyl arenas using different reactions like friddlecraft alkylation reactions, acylation reactions and even using diazenium salts in laboratories. Although we don't use these reactions extensively in laboratories anymore it is still important to understand these reactions and their underlying mechanisms.