 Hi, and welcome to the session. Let us discuss the following question. The question says, find the distance between parallel lines. First fact is, 15x plus 8y minus 34 is equal to 0. And 15x plus 8y plus 31 is equal to 0. Before solving this question, we should know the formula for finding the distance between two parallel lines. Parallel lines, whose equations are ax plus by plus c1 is equal to 0 and ax plus by plus c2 is equal to 0. Then the distance between these two parallel lines, that is d, is given by mod of c1 minus c2 upon square root of a square plus b square. With the help of this formula, we will solve this question. So always remember this formula. Let's now begin with the solution. First equation of line given to us is 15x plus 8y minus 34 is equal to 0. And second equation of line given to us is 15x plus 8y plus 31 is equal to 0. On comparing the first equation with ax plus by plus c1 is equal to 0, we find that a is equal to 50, b is equal to a, and c1 is equal to minus 34. On comparing the second equation with ax plus by plus c2 is equal to 0, we find that value of a and b is same, and value of c2 is 31. We know that distance between two parallel lines is given by mod of c1 minus c2 upon square root of a square plus b square. So we can now find the distance between these two parallel lines by substituting the value of c1, c2, a, and b in this formula. So distance between line one and line two, that is d is equal to mod of minus 34 minus 31 upon square root of 15 square plus 8 square. This is equal to 65 upon square root of 225 plus 64. And this is equal to 65 upon square root of 289. And this is equal to 65 upon 17. Hence the required distance between line one and line two is 65 by 17 units. This is our required answer. So this completes this session. Bye, and take care.