 Hi, welcome to the session. Let's discuss the question. Find the value of a, b, c and d from the equation. A 2 by 2 matrix whose elements are a minus v, 2a plus c, 2a minus v, 3c plus d is equal to another matrix whose elements are minus 1, 5, 0, 13. Here we will use the property that corresponding elements of equal matrices are equal. Let's start the solution by using the key idea that is as the given matrices are equal, therefore their corresponding elements must be equal. So comparing the corresponding elements, we get a minus v is equal to minus 1. Let us take it as number 1 equation. Again 2a plus c is equal to 5. Let us take it as number 2 equation. Minus v is equal to 0. Let us take it as third equation and again 3c plus d is equal to 13. Let us take it as fourth equation. Now we will solve all these equations on subtracting 1 from 3. We get 2a minus b minus a minus b is equal to 0 plus 1 which implies a is equal to 1. Now put the value of a a in 1 we get 1 minus 1 minus b is equal to minus 1 which implies v is equal to 2. Now put the value of a we get 2 1 plus c is equal to 5 which implies c is equal to 3. Again put the value of in 4 we get plus d is equal to 13 which implies 9 plus d is equal to 13 that is d is equal to 4. Hence a is equal to 1, b is equal to 2, c is equal to 3 and d is equal to 4 is our answer. Hope you have enjoyed the session. Okay and bye.