 Hi and welcome to the session. Let us discuss the following question. The question says showed that the points 1, 2, 2, 0 and 3 minus 2 are collinear. Let's now begin with the solution. Let the given points 1, 2, 2, 0 and 3 minus 2 are denoted by A, B and C respectively. Now points A, B and C will be collinear. The sum of the lengths of two line segments is equal to the third. Point A has coordinates 1, 2, point V has coordinates 2, 0 and point C has coordinates 3 minus 2. Now we will first find A, B. Now this is equal to square root of 2 minus 1 whole square plus 0 minus 2 whole square. Now this is equal to square root of 4 plus 1 and this is equal to square root of 5. Now we will find V, C. This is equal to square root of 3 minus 2 whole square plus minus 2 minus 0 whole square. And this is equal to square root of 1 plus 4 and this is equal to square root of 5. Now let's find A, C. This is equal to square root of 3 minus 1 whole square plus minus 2 minus 2 whole square. And this is equal to square root of 4 plus 60. This is equal to square root of 20 and this is equal to 2 into root 5. Now since A, B plus V, C that is root 5 plus root 5 that is 2 root 5 is equal to A, C. It is also equal to 2 root 5. Therefore we can say that points A, B and C are collinear. So this completes the session. Bye and take care.