 Preparation of alkyne by Grignard reagent, next one write down, by, on reaction with vinyl halide, Grignard reagent, on reaction with vinyl halide forms alkene with respect to, Grignard reagent, on reaction with vinyl halide forms alkene with respect to the alkyne group of Grignard reagent, the alkyne group of Grignard reagent, suppose this is the Grignard reagent RMGX and this reacts with vinyl halide, this is vinyl halide, CH2 double bond CHX, this position is vinylic position, this carbox, this is vinylic position, vinylic carbox, if you attach OH here, we call it as vinyl alcohol, one more position is there, CH2 double bond CH single bond CH2X, this carbon is allylic carbon, this one is allylic, the name of this compound is allylic allylic. So, is that a name for like, for this position, so the next position, if I would add another carbon would be, no, no, no, it is not there, okay, but this is not required for this reaction, but this position you must remember, this is allylic, okay, now what happens here, the product here are CH double bond CH2 plus MGX2, this is the reaction, okay, this R minus MG2 plus and X minus, right, R minus attack on to this carbon atom, this goes out as X minus MGX minus takes this, forms MGX, so what is the separation of alkytes, so already we have alkytes, oh this is alkytes also, okay, it means it is this, that is it, X can be improved, but this is fixed, it is fixed. So, on that side you cannot have more. No, this side you cannot have, this position is an allylic position, this group we call it as Vinay CH2 double bond CH and then open it, Vinay, okay, right on next, fitting reaction, fitting here, fitting here, what is fitting, fitting, what is here, fitting here, this one we have to write down, the fitting reagent we use is alkylidine, alkylidine tri-pinial phosphoryne, tri-pinial phosphoryne, this is vitic reagent, sometimes I ask this question, what is vitic reagent, alkylidine tri-pinial phosphoryne, okay, the formula is Ph3T tri-pinial double bond CH2, formula is Ph3T tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, tri-pinial phosphoryne, or any other alkali, CS3 we can take C2 and C5. The simplest one is, well R is hydrodynamic. So this one is DMTP double bond CS2. This is methylidine, CH2 double bond is methylidine. Okay? Double bond. This open double bond CH2. It's methylidine. Okay? Now the reaction is very simple. Suppose this is a method of repression of algae from aldehyde or keto. What is this keto? Now when this reacts with CH3P double bond CH2, the product of this reaction is CS3C double bond CH2, CS3 plus PH3P double bond. So this is a ketones. We take the reaction for ketones. Ketones, aldehyde. Repression of alkenes from aldehyde or keto. So what are these two together? Carbonyl compound. So there also you just replace the double bond. Double bond. So we don't always use this PH3P CH2. Generally we use this only. But instead of this we can use, suppose CS3, two also we can use. So you basically see that. Okay. That's what we have to do. This double bond, this double bond O and double bond CH2 you have to. This is an ethyl compound. Ethyl can't be compounded. Ethyl can't be compounded. Whatever we have here, this we should attach with this compound. So why is it called phosphory? Like what's the phosphory? Phosphory is illegal when you have P double bond O group. P double bond O. So if there's no P double bond O group. Double bond O is called P double bond O. Double bonded phosphorous is called P double bond O. Okay what is the product in this reaction? In this we do not have any exception. Mechanism is not there. We can discuss mechanism also and since this is a new reaction, so DHA and pattern is always fixed. We haven't done percentage composition of keto in all group. For that we have five, six methods. Okay. That we'll discuss. That one and one more thing like conformers, cyclohexane. That we'll discuss after finishing this chapter. Okay. Like in this one you see here we have tautomerism possible. Keto in all. This converts into this. In general what happens, keto form is more stable than enol form. Enol form. Why? Because C double bond O bond is stronger than this. In this one you have to compare and this is more stable. But if you take this, there are some rules for this. If you take this one, you know keto enol tautomerism is possible. And it converts into bond O and this converts into phenol. This one is aromatic. So since it is aromatic highly stable, so this 100% converts into this. So its comparison is 100% right. So in phenol we think reaction won't take place. Which one? This reaction? I'm not talking about this reaction. In this it won't take place. Because it is a reaction of only aldehyde. Converting of aldehyde and keto into alveol. So for us for example, shouldn't it have been C double bond C C H? No it's not. R will be hydrogen or aldehyde. That's why you say this entire probe with the tides of it is double bond C C H. Sir but then over there why doesn't the probe take place? Well, who think this? Oh yeah, no it didn't. But yeah. Okay, right now one last reaction by Pope elimination reaction. Right now last one by Pope elimination reaction. Right on. In this reaction, in this reaction, 3 degree amine oxide, in this reaction 3 degree amine oxide with at least 1 amine oxide with at least 1 beta hydrogen. Amine oxide with at least 1 beta hydrogen is heated add 150 degree Celsius. In this 3 degree amine oxide with at least one beta hydrogen, it is heated add 150 degree Celsius and it forms an It forms alkene and a derivative of hydroxylamide, hydroxylamide, RCH2, N double bond O, N double bond O, R2. So I saw some questions which nitrogen became pentaminate, directly with you. Sir, these guys have an MPD field. It was counting for me. No. No. No. No. No. No. No. No. No. No. No. No. No. No. Ok. So actually we see this one. So if you write this reaction this way, carbon, hydrogen, beta-carbon is this. So when you need this, this part, learn where to take this hydrogen, this comes over here and this goes over here. So it forms this product. RCS double bond CH2 and R2 OH. So it must be required at least one beta hydrogen for this reaction. At beta position we must have at least one hydrogen so that this hydrogen is taken up by this O- and forms hydroxyl energy. Okay, finished. We'll take a break. Preparation is done. We'll see some chemical reactions Let's see what happens.