 Hi and welcome to the session I am Deepika here. Let's discuss a question, gather the following list of numbers form an AP, if they form an AP, find the common difference D and write 3 more terms, minus 10, minus 6, minus 2, 2 and so on. Let us understand this concept. The given list of terms A1, A2, A3, so on forms an AP if the difference of a term and its preceding term is always constant. This constant is called the common difference of AP. Let us start the solution. Our given list of terms is minus 10, minus 6, minus 2, 2, so on. We have A2 minus A1 is equal to minus 6, minus minus 10 which is equal to 4. A3 minus A2 is equal to minus 2 minus minus of 6 which is equal to 4. Again A4 minus A3 is equal to 2 minus minus 2 which is equal to 4. That is, Ak plus 1 minus Ak is the same every time, that is it is constant. Therefore, the given list of numbers forms an AP with the common difference D is equal to, D is equal to 4. Now the next three terms are 4 is equal to 6, 6 plus 4 is equal to 10 and 10 plus 4 is equal to 14. So the answer for the above question is yes, the given list of terms forms an AP with common difference D is equal to 4 and the next three terms are 6, 10, 14. I hope the question is clear to you. Bye and have a good day.