 Hello and welcome to the session. Let us understand the following problem today. Find the area of a triangle with vertices as the point given in the following. We have 1, 0, 6, 0 and 4, 3. Now before adding the solution, let us look at the key idea. To find the area of a triangle by using determinants, given to us this as a triangle ABC with vertices x1, y1, x2, y2, x3, y3, then area of triangle ABC is given by it has equal to half into determinant of x1, y1, 1, x2, y2, 1, x3, y3, 1. Now let us write the solution now. Here x1, y1 is equal to 1, 0, x2, y2 is equal to 6, 0 and x3, y3 is equal to 4, 3. Now required area using the formula we have stated in the key idea that is half into determinant of x1, y1, 1, x2, y2, 1, x3, y3, 1. Which is equal to half into 1, 0, 1, 6, 0, 1, 4, 3, 1. Which is equal to half into 1 into 0 minus 3 minus 0, 6 minus 4, plus 1, et minus 0. Which is equal to half into 1 into minus 3 minus 0, plus 18. Which is equal to half into minus 3, plus 18. Which is equal to half into 15. Which is equal to 15 by 2. Therefore required area is 15 by 2. I hope you understood the problem. Bye and have a nice day.